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双持两把武器的狂乱攻速计算十分复杂,为了便于理解,下面先举一个实例:) N/ G0 j$ _9 W4 ^: T
[] 20级狂乱:SIAS=42 ~3 t, ~0 y0 F
[] 幻化之刃(PB):WSM=-30;IAS=0 3 q5 m# n: S( H
[] 巨神之剑(CS):WSM=10;IAS=0( q! E* M3 u3 |4 I! G
在动画初始时,系统会计算出一个具体的动画播放速率,具体步骤如下:4 J5 N- \: [9 h
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[] 首先获取当前的attackrate,也就是StatID=68(ItemStatCost.txt)。
" {( w, M" I. fattackrate = 100 - Right_Hand_WSM + SIAS = 100 - (-30) + 42 = 172
" ~" g- B- `/ }3 c1 N$ J/ _5 T/ R[] 这里需要注意的是Right_Hand指的是游戏角色的右手(手套上方),接下是计算全部武器的WSM_factor。. N* r9 ?% y2 _
WSM_factor = (Right_Hand_WSM + Leftt_Hand_WSM ) / 2 - Leftt_Hand_WSM = ((-30) + 10) / 2 - 10 = -20
$ D O* K$ _+ i[] 然后使用递缩公式将用于攻击的装备IAS折算为EIAS。
( E0 O) j7 h. [& eEIAS = (120 * (Right_Hand_IAS + Off_weapon_IAS)) / (Right_Hand_IAS + Off_weapon_IAS + 120) = (120 * (0 + 0)) / (120 + 0) = 0& l2 u% x' C2 }( B8 T
[] 接下来将以上的计算结果汇总到一起,开始计算a***tion_rate。! }* ^1 `# t. f6 _% R5 F0 K7 C; ]. L% L
a***tion_rate = EIAS + WSM_factor + attackrate - 30 = 0 + (-20) + 172 - 30 = 122
+ B8 y, a5 ?6 Q1 U [[] 这里需要注意的是a***tion_rate的上下限为别为175/15,最后开始计算实际动画播放速度。: q3 f) L0 J: y3 d+ J( s
a***tion_speed = (256 * a***tion_rate)/ 100 = (256 * 122) / 100 = 3120 ^0 I1 N8 F7 Y$ K7 U
[] 这里需要注意的是256并不是常数,而是animdata.d2中动画的特定值,不过玩家大部分攻击相关的动画都是使用256,在游戏中的每个Tick与a***tion_speed相加作为a***tion_position的增量,直到a***tion_position>=a***tion_length*256为止。, h/ i: @2 p& y( o$ q: w1 t3 F4 m
a***tion_position = a***tion_position + a***tion_speed
1 S# _% j$ r" v& r' S+ i[] 起始位置的a***tion_position从0开始计,然后将a***tion_position/256,以便获取当前的sequence_Frame并播放,当前的序列帧如下:
) k4 _: N7 m7 a: X1 B- iFrame = 1;a***tion_position = 0;sequence_Frame = 0
- Z9 z: P2 I/ A r4 EFrame = 2;a***tion_position = 312;sequence_Frame = 1
: Z! {) a4 \# d; p/ X6 D3 ` ^Frame = 3;a***tion_position = 624;sequence_Frame = 2
) P1 Z8 t7 C7 H+ PFrame = 4;a***tion_position = 936;sequence_Frame = 3
4 G; L* }% i3 `[] 现在可以看到,下一个sequence_Frame = (882+312)/256 = 4,同时这也是一个action_Frame,也就是说此时狂乱序列的第一个攻击帧为4F,所以此时会发动攻击(call技能srvdo函数)。对于狂乱来说,这是在增加SIAS,然后重新计算a***tion_speed,这里需要使用新的SIAS。如果攻击命中了目标,则切换武器,相当于激活了左手武器并参加攻速计算过程,下面假定达到最大值后的理想状态。- h* L4 t$ U- `$ s# B" C. L8 L1 x
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Frame = 5;a***tion_position = 1248;sequence_Frame = 42 p- V, d' n" |" o/ M8 K0 n
Frame = 6;a***tion_position = 1560;sequence_Frame = 65 C- ~1 d" u4 n( s3 i0 b
Frame = 7;a***tion_position = 1872;sequence_Frame = 7
. G5 I1 m8 ?2 [5 v( PFrame = 8;a***tion_position = 2184;sequence_Frame = 8
, }; V# |( t2 u) V[] 下一个sequence_Frame = (2184+312)/256 = 9,同时这也是一个action_Frame。接下来假定为理想状态,此后的步骤使用Lefr_Hand_WSM,这时会得到一个新的a***tion_speed=209,并继续播放动画。$ T/ y3 L! t6 ?# b/ {& Y% B, H
Frame = 9;a***tion_position = 2393;sequence_Frame = 9
, C; i0 Y& | u0 ]% [Frame = 10;a***tion_position = 2602;sequence_Frame = 10
; n% r1 ?/ l- P SFrame = 11;a***tion_position = 2811;sequence_Frame = 10
" Y5 Q5 g& a( \2 D9 S1 q6 TFrame = 12;a***tion_position = 3020;sequence_Frame = 11
, m/ \, ?) S; y( r+ e% o% e* @Frame = 13;a***tion_position = 3229;sequence_Frame = 12
8 g; H! z* T' ~! FFrame = 14;a***tion_position = 3438;sequence_Frame = 13
& p/ O7 N1 L2 L: o+ s, l/ QFrame = 15;a***tion_position = 3647;sequence_Frame = 14
' l9 W, V. _' Z! P; o' L! A- g/ zFrame = 16;a***tion_position = 3856;sequence_Frame = 15! K9 H( a4 k9 \
. S: @& b4 C7 ^* PFrame = 17;a***tion_position = 4065;sequence_Frame = 15
6 v' R8 Z4 v3 p0 y3 t: w XFrame = 18;a***tion_position = 4274;sequence_Frame = 16$ d1 r& [( u3 ]; T9 C# W- T# U
[] 下一个a***tion_position = 4274+312 = 4586,而狂乱的a***tion_length=17,则17*256 = 4352,而4586>4352,所以动画至此结束,总长度为18F。1 \' T* h" O) F* M9 N. K3 d
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* n$ H E% z" t# @, `) F- P7 r结合上文,可以简单推导出双持狂乱的完整攻速计算公式为:
1 _6 `1 k) p# A! b) a$ k7 e$ _[] 如果主手武器装备在左侧:
7 p2 j( n1 S* ^WSM1 = WSM_primary + WSM_secondary - (WSM_primary + WSM_secondary)/27 M6 g7 d! w6 j( s a0 g6 J" V
WSM2 = 2*WSM_secondary - (WSM_primary + WSM_secondary)/2
% k! I* T' u0 u. w" ]6 S3 e[] 如果主手武器装备在右侧: : l% g% n+ w7 F) c# R' r7 [
WSM1 = (WSM_primary + WSM_secondary)/2 + WSM_primary - WSM_secondary
& \1 n2 F% p1 O$ j$ {% S! j: |9 YWSM2 = (WSM_primary + WSM_secondary)/2
+ h& [$ L7 G! K- K! `[] EIAS部分的计算:
- X% q) m+ @8 W& @EIAS1 = [120*(OIAS + IASprimary)/(120 + OIAS + IASprimary)]
3 W/ ]9 {, \, c: m) d$ H8 `EIAS2 = [120*(OIAS + IASsecondary)/(120 + OIAS + IASsecondary)]
' ?9 m3 B" m8 @% Q3 K* k4 |5 P[] Acceleration部分的计算:! s1 _9 I: L6 p
Acceleration1 = 70 + SIAS + IAS1 - WSM13 T4 M& h Y' Q
Acceleration2 = 70 + SIAS + IAS2 - WSM2/ ^0 T5 V( E. P d6 `* ~3 |" _( I
[] FPA部分的计算: W, [1 a6 ?# C! C- l1 {
FPA_1 = {256*9/[256*Acceleration1/100]} - 1/ b( X( |3 S) L5 ~
FPA_2 = {(256*17 - fpa_1*[256*Acceleration1/100])/[256*Acceleration2/100]}
4 p/ `- S, C6 G" b# |FPA = FPA_1 + FPA_2
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